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JIPMER 2018
Exam
JIPMER
Year
2018
Subject
Chemistry
Chapter
Carboxylic Acid Derivatives

JIPMER 2018 · Chemistry · Carboxylic Acid Derivatives

Neopentyl chloride reacts with benzene in presence of a Lewis acid...

Neopentyl chloride reacts with benzene in presence of a Lewis acid (AlCl3)\left(\mathrm{AlCl}_3\right) to formNeopentyl chloride reacts with benzene in presence of a Lewis acid (AlCl_3) to formNeopentyl chloride reacts with benzene in presence of a Lewis acid (AlCl_3) to formNeopentyl chloride reacts with benzene in presence of a Lewis acid (AlCl_3) to formNeopentyl chloride reacts with benzene in presence of a Lewis acid (AlCl_3) to formNeopentyl chloride reacts with benzene in presence of a Lewis acid (AlCl_3) to form

Options

  1. AN _ 2 + 3 H _ 2 ⟶ 2N H _ 3 1 mole N _ 2 and 4 moles H _ 2 are taken in 15L flask at 27 ^ o C . After complete
  2. BN _ 2 + 3 H _ 2 ⟶ 2N H _ 3 1 mole N _ 2 and 4 moles H _ 2 are taken in 15L flask at 27 ^ o C . After complete
  3. CN _ 2 + 3 H _ 2 ⟶ 2N H _ 3 1 mole N _ 2 and 4 moles H _ 2 are taken in 15L flask at 27 ^ o C . After complete
  4. DN _ 2 + 3 H _ 2 ⟶ 2N H _ 3 1 mole N _ 2 and 4 moles H _ 2 are taken in 15L flask at 27 ^ o C . After complete

Correct answer

B. N _ 2 + 3 H _ 2 ⟶ 2N H _ 3 1 mole N _ 2 and 4 moles H _ 2 are taken in 15L flask at 27 ^ o C . After complete

Step-by-step solution

Neopentyl chloride reacts with benzene in presence of a Lewis acid (AlCl_3) to form
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