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JIPMER 2017
Exam
JIPMER
Year
2017
Subject
Chemistry
Chapter
Chemical Kinetics

JIPMER 2017 · Chemistry · Chemical Kinetics

In the following graph. The slope of line A B gives the information...

In the following graph. In the following graph. The slope of line A B gives the information of the The slope of line ABA B gives the information of the

Options

  1. Avalue of Ea2.303\frac{E_a}{2.303}
  2. Bvalue of 2.303Ea\frac{2.303}{E_a}
  3. Cvalue of −Ea2.303R-\frac{E_a}{2.303 R}
  4. Dvalue of −Ea2.303RT-\frac{E_a}{2.303 R T}

Correct answer

C. value of −Ea2.303R-\frac{E_a}{2.303 R}

Step-by-step solution

∵In⁡K=ln⁡A−EaRT\because \operatorname{In} K=\ln A-\frac{E_a}{R T} In⁡K=In⁡A−EaR⋅1T\operatorname{In} K=\operatorname{In} A-\frac{E_a}{R} \cdot \frac{1}{T} Thus, log⁡10K=log⁡A−Ea2.303RT\log _{10} K=\log A-\frac{E_a}{2.303 R T} log⁡K=log⁡A−Ea2.303⋅1T\log K=\log A-\frac{E_a}{2.303} \cdot \frac{1}{T}
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