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JIPMER2017ChemistryChemical Kinetics

For the chemical reaction, 2 O ₃ 3 O ₂ The reaction proceed as follows gathered O ₃ O ₂+ O (fast) O + O ₃ 2 O ₂ (slow) gathered The rate law expression will be

Options

  1. Ar=k^ [ O ₃ ]^2
  2. Br=k^ [ O ₃ ]^2 [ O ₂ ]⁻¹
  3. Cr=k^ [ O ₃ ] [ O ₂ ]
  4. DUnpredictable

Correct answer

B. r=k^ [ O ₃ ]^2 [ O ₂ ]⁻¹

Step-by-step solution

As slowest step is the rate determining step. Hence, from slow reaction, r=K[ O ] [ O ₃ ]...(i) From fast reaction, K_C= [ O ₂ ][ O ] [ O ₃ ] aligned [ O ] & = K_C [ O ₃ ] [ O ₂ ] , i.e. r & = K_C [ O ₃ ] [ O ₂ ] [ O ₃ ] aligned K_C [ O ₃ ]^2 [ O ₂ ]⁻¹ Rate (r)=K^ [ O ₃ ]^2 [ O ₂ ]⁻¹ (K^ =K_C K )

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