A hypothetical reaction, X_2+Y_2 2 X Y follows the following mechanism X_2 leftharpoons X+X . . . . . . . fast X+Y_2 X Y+Y slow X+Y X Y .......... fast The order of the overall reaction is

Correct answer: B. 3 / 2 Rate =k[X][Y_2] But, k=([X]^2)/([X_2]) or, [X]= k ·[X_2] Rate =k · k [X_2] [Y_2]=k^ [X_2]^ 1 / 2 [Y_2] Thus, order, =1+(1)/(2)=(3)/(2)

JIPMER 2015

Exam: JIPMER
Year: 2015
Subject: Chemistry
Chapter: Chemical Kinetics

JIPMER 2015 · Chemistry · Chemical Kinetics

A hypothetical reaction, X_2+Y_2 2 X Y follows the following...

A hypothetical reaction,

X_2+Y_2 \longrightarrow 2 X Y

follows the following mechanism

X_2 \rightleftharpoons X+X \ldots . . . . . .

. fast

X+Y_2 \longrightarrow X Y+Y \ldots \ldots

slow

X+Y \longrightarrow X Y

.......... fast The order of the overall reaction is

Options

A $2$
B $3 / 2$
C $1$
D $0$

Correct answer

B. $3 / 2$

Step-by-step solution

Rate

=k[X]\left[Y_2\right]

But,

k=\frac{[X]^2}{\left[X_2\right]}

or,

[X]=\sqrt{k \cdot\left[X_2\right]}

Rate

=k \cdot \sqrt{k} \sqrt{\left[X_2\right]}\left[Y_2\right]=k^{\prime}\left[X_2\right]^{1 / 2}\left[Y_2\right]

Thus, order,

=1+\frac{1}{2}=\frac{3}{2}

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