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JIPMER 2006
Exam
JIPMER
Year
2006
Subject
Chemistry
Chapter
Ionic Equilibrium

JIPMER 2006 · Chemistry · Ionic Equilibrium

Given pH of a solution A is 3 and it is mixed with another solution...

Given pH of a solution AA is 3 and it is mixed with another solution BB having pH 2 . If both mixed, then resultant pH of the solution will be :

Options

  1. A3.2
  2. B1.9
  3. C3.4
  4. D3.5

Correct answer

B. 1.9

Step-by-step solution

pH of  A=3pH of B=2∴[H+]=10−3M,[H+]=10−2M Total [H+]=10−3+10−2=10−3+10×10−3=11×10−3∴pH=−log⁡10[H+]=−log⁡(11×10−3)=3−log⁡11=3−1.04=1.96\begin{aligned} & \mathrm{pH} \text{\text{ of } } A=3 \quad \mathrm{pH} \text{ of } B=2 \\ & \therefore\left[\mathrm{H}^{+}\right]=10^{-3} \mathrm{M}, \quad\left[\mathrm{H}^{+}\right]=10^{-2} \mathrm{M} \\ & \text{ Total }\left[\mathrm{H}^{+}\right] \\ & =10^{-3}+10^{-2}=10^{-3}+10 \times 10^{-3} \\ & =11 \times 10^{-3} \\ & \therefore \quad \mathrm{pH}=-\log _{10}\left[\mathrm{H}^{+}\right]=-\log \left(11 \times 10^{-3}\right) \\ & =3-\log 11 \\ & =3-1.04=1.96 \\ & \end{aligned}
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