JIPMER 2012
- Exam
- JIPMER
- Year
- 2012
- Subject
- Chemistry
- Chapter
- Ionic Equilibrium
JIPMER 2012 · Chemistry · Ionic Equilibrium
The solubility product of Hg_2 I _2 is equal to
The solubility product of \mathrm{I} is equal to
Options
- A\left[\mathrm{Hg}_2^{2+}\right]\left[\mathrm{I}^{-}\right]
- B\left[\mathrm{Hg}^{2+}\right]\left[\mathrm{I}^{-}\right]
- C\left[\mathrm{Hg}_2^{2+}\right]\left[\mathrm{I}^{-}\right]^2
- D\left[\mathrm{Hg}^{2+}\right]\left[\mathrm{I}^{-}\right]^2
Correct answer
C. \left[\mathrm{Hg}_2^{2+}\right]\left[\mathrm{I}^{-}\right]^2
Step-by-step solution
\mathrm{Hg}_2 _2(s) \rightleftharpoons \mathrm{Hg}_2^{2+}+2 ^{-}
\therefore \quad K_{s p}=\left[\mathrm{Hg}_2^{2+}\right]\left[^{-}\right]^2