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JIPMER 2018
Exam
JIPMER
Year
2018
Subject
Chemistry
Chapter
Redox Reactions

JIPMER 2018 · Chemistry · Redox Reactions

When hydrogen peroxide is added to acidified solution of dichromate...

When hydrogen peroxide is added to acidified solution of dichromate Cr2O72−\mathrm{Cr}_2 \mathrm{O}_7^{2-}, a deep blue coloured complex of chromic peroxide CrO5\mathrm{CrO}_5 is formed. Oxidation state of Cr in CrO5\mathrm{CrO}_5 isWhen hydrogen peroxide is added to acidified solution of dichromate Cr_2 O_7^ 2- , a deep blue coloured complex of

Options

  1. A+5+5
  2. B+3+3
  3. C+6+6
  4. D−10- 10

Correct answer

C. +6+6

Step-by-step solution

When H2O2\mathrm{H}_2 \mathrm{O}_2 is added to an acidified solution of dichromate Cr2O72−\mathrm{Cr}_2 \mathrm{O}_7^{2-}, a deep blue complex chromic peroxide, CrO5\mathrm{CrO}_5 is formed. Cr2O72−+2H++4H2O2⟶2CrO(O2)2+5H2O\mathrm{Cr}_2 \mathrm{O}_7^{2-}+2 \mathrm{H}^{+}+4 \mathrm{H}_2 \mathrm{O}_2 \longrightarrow 2 \mathrm{CrO}\left(\mathrm{O}_2\right)_2+5 \mathrm{H}_2 \mathrm{O} This deep blue coloured complex has the following structure When hydrogen peroxide is added to acidified solution of dichromate Cr_2 O_7^ 2- , a deep blue coloured complex of Let the oxidation state of Cr be x . In CrO(O2)2\mathrm{CrO}\left(\mathrm{O}_2\right)_2x+(−1)4+(−2)=0x−6=0x=+6\begin{aligned} x+(-1) 4+(-2) & =0 \\ x-6 & =0 \\ x & =+6\end{aligned}$$
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