Assertion: Equivalent weight of NH_3 in the reaction, N_2 arrow NH_3 is 17 / 3 while that of N_2 is 28/6. Reason : Equivalent weight = Molecular weight array c Number of e^ - lost or gained per mole array

Correct answer: A. If both assertion and reason are true and reason is the correct explanation of assertion. : 0 ~N _2+6 e^ - arrow 2 ~N^ 3- Equivalent weight of NH_3=(14+3)/(3)=(17)/(3) (Mol. wt. of NH_3=17 ) While, equivalent weight of N_2=(14 × 2)/(6)=(28)/(6)

AIIMS 2017

Exam: AIIMS
Year: 2017
Subject: Chemistry
Chapter: Redox Reactions

AIIMS 2017 · Chemistry · Redox Reactions

Assertion: Equivalent weight of NH_3 in the reaction, N_2 arrow...

Assertion: Equivalent weight of

\mathrm{NH}_3

in the reaction,

\mathrm{N}_2 \rightarrow \mathrm{NH}_3

17 / 3

while that of

\mathrm{N}_2

is 28/6. Reason : Equivalent weight =\frac{\text{ Molecular weight }}{\begin{\text{ array }}{c}\text{ Number\text{ of } } e^{-} \text{lost or gained } \\ \text{ per mole }\end{\text{ array }}}

Options

AIf both assertion and reason are true and reason is the correct explanation of assertion.
BIf both assertion and reason are true but reason is not the correct explanation of assertion.
CIf assertion is true but reason is false.
DIf both assertion and reason are false.

Correct answer

A. If both assertion and reason are true and reason is the correct explanation of assertion.

Step-by-step solution

: \stackrel{0}{\mathrm{~N}}_2+6 e^{-} \rightarrow 2 \mathrm{~N}^{3-}

\therefore \quad

Equivalent weight of

\mathrm{NH}_3=\frac{14+3}{3}=\frac{17}{3}

(Mol. wt. of

\mathrm{NH}_3=17

) While, equivalent weight of

\mathrm{N}_2=\frac{14 \times 2}{6}=\frac{28}{6}

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