In order to prepare one litre 1 N solution of KMnO_4 , how many grams of KMnO_4 are required, if the solution to be used in acid medium for oxidation?

Correct answer: C. 31.60 g In acidic medium, aligned & MnO_4^ - +8 H^ + +5 e^ - Mn^ 2+ +4 H_2 O & (From KMnO_4 ) aligned Hence, equivalent weight of KMnO_4 in acidic medium = Moleculer weight 5 =(158)/(5)=31.6 1 ~N solution can be prepared by dissolving 31.6 g KMnO_4 in 1L solution.

JIPMER 2015

Exam: JIPMER
Year: 2015
Subject: Chemistry
Chapter: Solutions

JIPMER 2015 · Chemistry · Solutions

In order to prepare one litre 1 N solution of KMnO_4 , how many...

In order to prepare one litre 1 N solution of

\mathrm{KMnO}_4

, how many grams of

\mathrm{KMnO}_4

are required, if the solution to be used in acid medium for oxidation?

Options

A128 g
B41.75 g
C31.60 g
D62.34 g

Correct answer

C. 31.60 g

Step-by-step solution

In acidic medium,

\begin{aligned} & \mathrm{MnO}_4^{-}+8 \mathrm{H}^{+}+5 e^{-} \longrightarrow \mathrm{Mn}^{2+}+4 \mathrm{H}_2 \mathrm{O} \\ & \text{ (From } \mathrm{KMnO}_4 \text{ ) }\end{aligned}

Hence, equivalent weight of

\mathrm{KMnO}_4

in acidic medium

=\frac{\text{ Moleculer weight }}{5}=\frac{158}{5}=31.6 \therefore 1 \mathrm{~N}

solution can be prepared by dissolving 31.6 g

\mathrm{KMnO}_4

in 1L solution.

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