If V =1 litre, 10 mole of H ₂ and 10 mole of N ₂ gas are mixed at temperature 26^ C , then calculate pressure of the gas.

Step-by-step solution

According to ideal gas equation, pV = nRT . Given, V =1 ~L , n ₁=10 mole, n ₂=10 mole. T =26^ C =299 ~K . On substituting the given values in above equation, we get. aligned p & = 20 ~mol 0.0821 ~L ~atm ~mol ⁻¹ ~K ⁻¹ 299 ~K 1 ~L & =491 ~atm . aligned