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JIPMER2016ChemistryThermodynamics (C)

At 27^ C , one mole of an ideal gas is compressed isothermally and reversibly from a pressure of 2 atm to 10 atm . Choose the correct option from the following.

Options

  1. AChange in internal energy is positive
  2. BHeat is negative
  3. CWork done is -965.84 cal
  4. DAll are incorrect

Correct answer

B. Heat is negative

Step-by-step solution

Work done in isothermal reversible process is w=-2.303 n R T ₁₀ p₁ p₂ Given, aligned n & =1, R=2 cal K ⁻¹ ~mol ⁻¹ T & =(27+273) K =300 ~K p₁ & =2 ~atm , p₂=10 ~atm aligned aligned w & =-2.303 1 2 300 ₁₀ 2 10 w & =+965.54 cal aligned For isothermal change, U=0 Now, from first law of thermodynamics, aligned & q= U-W=0-965.84 cal & q=-965.84 cal aligned

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