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JIPMER 2005
Exam
JIPMER
Year
2005
Subject
Chemistry
Chapter
Thermodynamics (C)

JIPMER 2005 · Chemistry · Thermodynamics (C)

In an isothermal process

In an isothermal process

Options

  1. AΔH=ΔE+PΔV\Delta H=\Delta E+P \Delta V
  2. BΔH=W\Delta H=W
  3. CΔH=ΔE\Delta H=\Delta E
  4. DΔH=SΔT\Delta H=S \Delta T

Correct answer

B. ΔH=W\Delta H=W

Step-by-step solution

In an isothermal process, the temperature is constant. So, ΔE=0\quad \Delta E=0 Hence ΔH=PΔV\Delta H=P \Delta V (As, ΔH=ΔE+PΔV\Delta H=\Delta E+P \Delta V ) ΔH=W\Delta H=W (∵W=PΔV)\qquad (\because W=P \Delta V)
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