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JIPMER 2015
Exam
JIPMER
Year
2015
Subject
Chemistry
Chapter
Thermodynamics (C)

JIPMER 2015 · Chemistry · Thermodynamics (C)

What would be the heat released when an aqueous solution containing...

What would be the heat released when an aqueous solution containing 0.5 mole of HNO3\mathrm{HNO}_3 is mixed with 0.3 mole of OH−\mathrm{OH}^{-}? (enthalpy of neutralisation is -57.1 kJ )

Options

  1. A28.5 kJ
  2. B17.1 kJ
  3. C45.7 kJ
  4. D1.7 kJ

Correct answer

B. 17.1 kJ

Step-by-step solution

0.5 mole of HNO3\mathrm{HNO}_3 equivalents to 0.5 mole of H+\mathrm{H}^{+}. But only 0.3 mole of OH−\mathrm{OH}^{-}ions are available. Thus, 0.3 mole of H+\mathrm{H}^{+}ions will combine with 0.3 mole of OH−\mathrm{OH}^{-}ions to form 0.3 mole of H2O\mathrm{H}_2 \mathrm{O} and 0.2 mole of H+\mathrm{H}^{+}ions will remain unreacted. Heat evolved when 1 mole of H+\mathrm{H}^{+}ions combine with 1 mole of OH−\mathrm{OH}^{-}ions =57.1 kJ=57.1 \mathrm{~kJ}. Therefore, heat evolved wher 0.3 mole of H+\mathrm{H}^{+}ions combine with 0.3 mole of OH−\mathrm{OH}^{-}ions =0.3×57.1=17.13 kJ=0.3 \times 57.1=17.13 \mathrm{~kJ}.
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