Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app

JIPMER 2019

Exam: JIPMER
Year: 2019
Subject: Physics
Chapter: Alternating Current

JIPMER 2019 · Physics · Alternating Current

Find resonance frequency in the given circuit

Find resonance frequency in the given circuit

Find resonance frequency in the given circuit

Options

A $\frac{1}{\sqrt{L C}}$
B $\frac{2}{\sqrt{L C}}$
C $\frac{1}{2 \sqrt{L C}}$
D $\frac{4}{\sqrt{L C}}$

Correct answer

A. $\frac{1}{\sqrt{L C}}$

Step-by-step solution

In the given circuit diagram, both inductors of inductance L are parallel to each other, hence

\mathrm{L}_{\text{eg }}=\frac{\mathrm{L}_1 \mathrm{ L}_2}{\mathrm{ L}_1+\mathrm{L}_2}=\frac{\mathrm{L} . \mathrm{L}}{\mathrm{L}+\mathrm{L}}=\frac{\mathrm{L}}{2}

Similarly,

\mathrm{C}_{\mathrm{eg}}=\mathrm{C}_1+\mathrm{C}_2=\mathrm{C}+\mathrm{C}=2

\mathrm{C}

\therefore

Resonance frequency

\omega_1=\frac{1}{\sqrt{

\mathrm{L}_{

\mathrm{cg}

} \cdot

\mathrm{C}_{

\mathrm{cg}

}}}=\sqrt{\frac{1}{\frac{

\mathrm{L}

}{2} \cdot 2

\mathrm{C}

}}=\sqrt{\frac{1}{

\mathrm{LC}

}}=\frac{1}{\sqrt{

\mathrm{LC}

}}

Practice Alternating Current on Quantrex Academy →

More from Alternating Current

A step down transformer connected to an a.c. mains of 220 V is made to operate at 5.5 V… MHT CET Medical 2026 Which phasor diagram represents LCR circuit at resonance? MHT CET Medical 2026 For an R-L series circuit, the power factor is 3 2 , for R-L frequency f Hz. If the… MHT CET Medical 2026 In an AC circuit, the current is I = 100 (5t) A. The value of I_ rms is MHT CET Medical 2026 The ratio of power factor of purely resistive circuit to purely reactive circuit is ( 0^… MHT CET Medical 2026 In an LCR series circuit, at resonance, MHT CET Medical 2026 In an AC circuit, E and I are given by E = 150 (150t) V and I = 150 (150t + (π)/(3)) A.… MHT CET Medical 2026 A series LCR circuit is connected across a source E of e.m.f. E=15 ( 50 π t- (π)/(3)).… MHT CET Medical 2026 Full Alternating Current list All JIPMER PYQs