JIPMER2009PhysicsAlternating Current
The primary and secondary coils of a transformer have 50 and 1500 turns respectively. If the magnetic flux linked with the primary coil is given by = ₀+4 t , where is in weber, t is time in second and ₀ is a constant, the output voltage across the secondary coil is
Options
- A90 V
- B120 V
- C220 V
- D30 V
Correct answer
B. 120 V
Step-by-step solution
The magnetic flux linked with the primary c is given by = ₀+4 t So, voltage across primary aligned V_p & = d d t = d d t ( ₀+4 t ) & =4 volt ( as ₀= . consta aligned Also, we have N_p=50 and N_s=1500 From relation, or aligned V_s V_p & = N_s N_p V_s & =V_p N_s N_p & =4 ( 1500 50 ) & =120 ~V aligned