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JIPMER 2006
Exam
JIPMER
Year
2006
Subject
Physics
Chapter
Alternating Current

JIPMER 2006 · Physics · Alternating Current

In a L-C-R circuit, the capacitance is made one-fourth, then what...

In a L−C−RL-C-R circuit, the capacitance is made one-fourth, then what should be change in inductance, so that the circuit remains in resonance?

Options

  1. A8 times
  2. B1/41 / 4 times
  3. C2 times
  4. D4 times

Correct answer

D. 4 times

Step-by-step solution

Resonance frequency f=12πLCf=\frac{1}{2 \pi \sqrt{L C}} For the circuit to remain in resonance, LC=\sqrt{L C}= constant orL1C1=L2C2orLC=L2C4∴L2=4L\begin{aligned} or \quad L_1 C_1 & =L_2 C_2 \\ or \quad L C & =L_2 \frac{C}{4} \\ \therefore L_2 & =4 L\end{aligned}\therefore$ Inductance should be change to four times.
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