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JIPMER 2010
Exam
JIPMER
Year
2010
Subject
Physics
Chapter
Atomic Physics

JIPMER 2010 · Physics · Atomic Physics

Wavelength of light emitted from second orbit to first orbit in a...

Wavelength of light emitted from second orbit to first orbit in a hydrogen atom is

Options

  1. A6563A˚6563 Å
  2. B4102A˚4102 Å
  3. C4861A˚4861 Å
  4. D1215A˚1215 Å

Correct answer

D. 1215A˚1215 Å

Step-by-step solution

Wavelength of light 1λ=R(112−122)⇒1λ=1.097×107×34∴λ=1.215×10−7 m=1215A˚\begin{aligned} & \frac{1}{\lambda}=R\left(\frac{1}{1^2}-\frac{1}{2^2}\right) \\ & \Rightarrow \quad \frac{1}{\lambda}=1.097 \times 10^7 \times \frac{3}{4} \\ & \therefore \quad \lambda=1.215 \times 10^{-7} \mathrm{~m}=1215 Å \end{aligned}
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