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JIPMER 2016
Exam
JIPMER
Year
2016
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

JIPMER 2016 · Physics · Center of Mass, Momentum and Collision

Particles of masses m, 2 m, 3 m, , n m are placed on the same line...

Particles of masses m,2m,3m,…,nmm, 2 m, 3 m, \ldots, n m are placed on the same line at distances L,2L,3L,…,nLL, 2 L, 3 L, \ldots, n L from OO. The distance of centre of mass from OO isParticles of masses m, 2 m, 3 m, , n m are placed on the same line at distances L, 2 L, 3 L, , n L from O . The

Options

  1. A(2n+1)L4\frac{(2 n+1) L}{4}
  2. BL(2n+1)\frac{L}{(2 n+1)}
  3. Cn(n2+1)L2\frac{n\left(n^2+1\right) L}{2}
  4. D(2n+1)L3\frac{(2 n+1) L}{3}

Correct answer

D. (2n+1)L3\frac{(2 n+1) L}{3}

Step-by-step solution

Particles of masses m, 2 m, 3 m, , n m are placed on the same line at distances L, 2 L, 3 L, , n L from O . The ∵xCM=mL+2m×2L+…+nm×nLm+2m+…+nm\because \quad x_{C M}=\frac{m L+2 m \times 2 L+\ldots+n m \times n L}{m+2 m+\ldots+n m}=L(12+22+…+n2)(1+2+…+n)=LΣn2Σn=Ln(n+1)(2n+1)6n(n+1)2=(2n+1)L3\begin{aligned} & =\frac{L\left(1^2+2^2+\ldots+n^2\right)}{(1+2+\ldots+n)} \\ & =L \frac{\Sigma n^2}{\Sigma n}=L \frac{\frac{n(n+1)(2 n+1)}{6}}{\frac{n(n+1)}{2}} \\ & =\frac{(2 n+1) L}{3}\end{aligned}$$
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