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NEET2016PhysicsCenter of Mass, Momentum and CollisionActual

A bullet of mass 10 g moving horizontally with a velocity of 400 m s - 1 strikes a wooden block of mass 2 kg which is suspended by a light inextensible string of length 5 m. As a result, the centre of gravity of the block is found to rise a vertical distance of 10 cm. The speed of the bullet after it emerges out horizontally from the block will be

Options

  1. A100 m s - 1
  2. B80 m s - 1
  3. C120 m s - 1
  4. D160 m s - 1

Correct answer

C. 120 m s - 1

Step-by-step solution

CM rises through height h, so its velocity after collision = 2 g h Apply conservation of linear momentum. 0.01 × 400 = 2 × 2 g h + 0.01 × v ⇒ v = 120 m/s

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