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NEET 2016
Exam
NEET
Year
2016
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

NEET 2016 · Physics · Center of Mass, Momentum and Collision

A bullet of mass 10 g moving horizontally with a velocity of 400m s...

A bullet of mass 10g10 g moving horizontally with a velocity of 400ms−1400m{s}^{- 1} strikes a wooden block of mass 2kg2 kg which is suspended by a light inextensible string of length 5m.5 m. As a result, the centre of gravity of the block is found to rise a vertical distance of 10cm.10 cm. The speed of the bullet after it emerges out horizontally from the block will be

Options

  1. A100ms−1100m{s}^{- 1}
  2. B80ms−180m{s}^{- 1}
  3. C120ms−1120m{s}^{- 1}
  4. D160ms−1160m{s}^{- 1}

Correct answer

C. 120ms−1120m{s}^{- 1}

Step-by-step solution

CM rises through height h, so its velocity after collision =2gh= \sqrt{2gh}

Apply conservation of linear momentum.

0.01×400=2×2gh+0.01×v0.01 \times 400 = 2 \times \sqrt{2gh} + 0.01 \times v

⇒v=120m/s⇒ v = 120m/s
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