You are given resistance wire of length 50 cm and a battery of...

Let $R$ be the resistance of the wire (a) $H_1=\frac{V^2 t}{R}$ (b) Resistance of each part will be $R$ / 2. When they are connected in parallel, the resistance will be $R / 4$. Hence, $H_2=\frac{4 v^2 t}{R}$ (c) In case of four wires connected in parallel, the resistance will be $R$ / 8 $\therefore H_3=\frac{8 V^2 t}{R}$ (d) $H_4=\frac{V^2 t}{[R / 2]}=\frac{2 V^2 \cdot t}{R}$ Hence, largest amount of heat will be generated in case of four parts connected in parallel.