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JIPMER 2015
Exam
JIPMER
Year
2015
Subject
Physics
Chapter
Current Electricity

JIPMER 2015 · Physics · Current Electricity

A wire of resistance 10 is bent to form a complete circle. Find its...

A wire of resistance 10Ω10 \Omega is bent to form a complete circle. Find its resistance between two diametrically opposite point. A wire of resistance 10 is bent to form a complete circle. Find its resistance between two diametrically opposite point.

Options

  1. A5Ω5 \Omega
  2. B2.5Ω2.5 \Omega
  3. C1.25Ω1.25 \Omega
  4. D103Ω\frac{10}{3} \Omega

Correct answer

B. 2.5Ω2.5 \Omega

Step-by-step solution

The wires ADCA D C and ABCA B C will have resistance 5Ω5 \Omega each. These two are joined in parallel between AA and CC. The equivalent resistance RR between AA and CC is, therefore given by R=5Ω×5Ω5Ω+5Ω=2.5ΩR=\frac{5 \Omega \times 5 \Omega}{5 \Omega+5 \Omega}=2.5 \Omega
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