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JIPMER 2015
Exam
JIPMER
Year
2015
Subject
Physics
Chapter
Current Electricity

JIPMER 2015 · Physics · Current Electricity

The ammeter shown in figure consists of a 480 coil connected in...

The ammeter shown in figure consists of a 480Ω480 \Omega coil connected in parallel to a 20Ω20 \Omega shunt. The reading of ammeter is The ammeter shown in figure consists of a 480 coil connected in parallel to a 20 shunt. The reading of ammeter is

Options

  1. A0.125 A
  2. B1.67 A
  3. C0.13 A
  4. D0.67 A

Correct answer

A. 0.125 A

Step-by-step solution

The equivalent resistance of the ammeter is (480)(20)480+20=19.2Ω\frac{(480)(20)}{480+20}=19.2 \Omega The equivalent resistance of the circuit is 1408+19.2Ω=160Ω1408+19.2 \Omega=160 \Omega The current, i=20 V160Ω=0.125 Ai=\frac{20 \mathrm{~V}}{160 \Omega}=0.125 \mathrm{~A} Hence, ammeter reading is 0.125 A .
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