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JIPMER 2015
Exam
JIPMER
Year
2015
Subject
Physics
Chapter
Current Electricity

JIPMER 2015 · Physics · Current Electricity

The galvanometer resistance is 30 and it is connected to 2 V...

The galvanometer resistance is 30Ω30 \Omega and it is connected to 2 V battery along with a resistance 2000Ω2000 \Omega in series. A full scale deflection of 25 divisions is obtained. In order to reduce this deflection to 20 divisions, the resistance in series should be

Options

  1. A2470Ω2470 \Omega
  2. B2320Ω2320 \Omega
  3. C2180Ω2180 \Omega
  4. D2210Ω2210 \Omega

Correct answer

A. 2470Ω2470 \Omega

Step-by-step solution

Total initial resistance =G+R=30+2000=2030Ω=G+R=30+2000=2030 \Omega Current i=22030 A\quad i=\frac{2}{2030} \mathrm{~A} Let xx be the effective resistance of the circuit, then 2V=2030×22030×103=x×22.5⇒x=2×2.52×103=2500Ω\begin{aligned} 2 V & =2030 \times \frac{2}{2030} \times 10^3 \\ & =x \times \frac{2}{2.5} \\ \Rightarrow \quad x & =\frac{2 \times 2.5}{2} \times 10^3 \\ & =2500 \Omega\end{aligned}\thereforeResistancetobeaddedResistance to be added=2500-30=2470 \Omega$
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