Exam

JIPMER

Year

2016

Subject

Physics

Chapter

Current Electricity

JIPMER 2016 · Physics · Current Electricity

In the given figure, potential difference between A and B is

In the given figure, potential difference between $A$ and $B$ is

Step-by-step solution

Equivalent resistance, $R=10+\frac{10}{2}=15 \mathrm{k} \Omega$ $\therefore \quad$ Current, $I=\frac{V}{R}=\frac{30}{15 \times 10^3}=2 \times 10^{-3} \mathrm{~A}$ Hence potential difference between A and B, $V=\left(\frac{2 \times 10^{-3}}{2}\right) \times 10 \times 10^3=10 \mathrm{~V}$