For the network shown in the figure, the value of the current i is

Step-by-step solution

The circuit given resembles the balanced Wheatstone Bridge as 4 6 = 2 3 . Thus, middle arm containing 4 resistance will be ineffective and no current flows through it. The equivalent circuit is shown as below : Net resistance of A B and B C , R^ =4+2=6 Net resistance of A D and D C , R^ =6+3=9 Thus, parallel combination of R^ and R^ gives gathered R= R^ R^ R^ +R^ = 6 9 6+9 = 54 15 = 18 5 gathered Hence, current i= V R = V 18 / 5 = 5 V 18