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JIPMER 2007
Exam
JIPMER
Year
2007
Subject
Physics
Chapter
Current Electricity

JIPMER 2007 · Physics · Current Electricity

When a wire of uniform cross-section a , length l and resistance R...

When a wire of uniform cross-section aa, length ll and resistance RR is bent into a complete circle, resistance between two of diametrically opposite points will beWhen a wire of uniform cross-section a , length l and resistance R is bent into a complete circle, resistance between

Options

  1. AR4\frac{R}{4}
  2. BR8\frac{R}{8}
  3. C4R4 R
  4. DR2\frac{R}{2}

Correct answer

A. R4\frac{R}{4}

Step-by-step solution

When wire is bent to form a complete circle then 2πr=R⇒r=R2π2 \pi r=R \Rightarrow r=\frac{R}{2 \pi} When a wire of uniform cross-section a , length l and resistance R is bent into a complete circle, resistance between Resistance of each semicircle =πr=πR2π=R2=\pi r=\frac{\pi R}{2 \pi}=\frac{R}{2} Thus, net resistance in parallel combination of two semicircular resistance R′=R2×R2R2+R2=R24R=R4R^{\prime}=\frac{\frac{R}{2} \times \frac{R}{2}}{\frac{R}{2}+\frac{R}{2}}=\frac{\frac{R^2}{4}}{R}=\frac{R}{4}
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