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JIPMER 2005
Exam
JIPMER
Year
2005
Subject
Physics
Chapter
Current Electricity

JIPMER 2005 · Physics · Current Electricity

When a certain current is passed in the circuit as shown in figure,...

When a certain current is passed in the circuit as shown in figure, 10 kcal of heat is produced in 5Ω5 \Omega resistance. How much heat is produced in 4Ω4 \Omega resistance? When a certain current is passed in the circuit as shown in figure, 10 kcal of heat is produced in 5 resistance. How

Options

  1. A4 kcal
  2. B2 kcal
  3. C5 kcal
  4. D3 kcal

Correct answer

B. 2 kcal

Step-by-step solution

Heat produced in 5Ω=10kcal5 \Omega=10 \mathrm{kcal} Now from the relation. H1=i12R1tori12=H1R1tori12=H15tH_1=i_1^2 R_1 t or i_1^2=\frac{H_1}{R_1 t} or \quad i_1^2=\frac{H_1}{5 t} ...(1) Again, 5×i1=10×i25 \times i_1=10 \times i_2 or i2=i12i_2=\frac{i_1}{2} When a certain current is passed in the circuit as shown in figure, 10 kcal of heat is produced in 5 resistance. How
When a certain current is passed in the circuit as shown in figure, 10 kcal of heat is produced in 5 resistance. How Now heat produced in 4Ω4 \Omega resistance is H2=i22R2ti22=H2R2t\begin{aligned} H_2 & =i_2^2 R_2 t \\ i_2^2 & =\frac{H_2}{R_2 t}\end{aligned} or i124=H24tori12=H2t\quad \frac{i_1^2}{4}=\frac{H_2}{4 t} or i_1^2=\frac{H_2}{t} ...(2) From eqs. (1) and (2) H2t=H15t or H2=H15=102=2kcal\begin{aligned} \frac{H_2}{t} & =\frac{H_1}{5 t} \\ \text{ or } \quad H_2 & =\frac{H_1}{5}=\frac{10}{2}=2 \mathrm{kcal}\end{aligned}
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