A current of 1.6A is passed through a solution of CuSO_4 . How many Cu^ ++ ions are liberated in one minute? (Electronic charge =1.6 × 10^ -19 C )

Correct answer: A. 3 × 10^ 20 Charge flowing in one minute q=I × t=1.6 × 60 C Charge required to liberate one copper ion 2 C Number of Cu^ 2+ liberated = 1.6 × 60 2 × 1.6 × 10^ -19 =3 × 10^ 20

JIPMER 2012

Exam: JIPMER
Year: 2012
Subject: Physics
Chapter: Current Electricity

JIPMER 2012 · Physics · Current Electricity

A current of 1.6A is passed through a solution of CuSO_4 . How many...

A current of 1.6A is passed through a solution of

\mathrm{CuSO}_4

. How many

\mathrm{Cu}^{++}

ions are liberated in one minute? (Electronic charge

=1.6 \times 10^{-19} \mathrm{C}

)

Options

A $3 \times 10^{20}$
B $3 \times 10^{10}$
C $6 \times 10^{20}$
D $6 \times 10^{10}$

Correct answer

A. $3 \times 10^{20}$

Step-by-step solution

Charge flowing in one minute

q=I \times t=1.6 \times 60 \mathrm{C}

Charge required to liberate one copper ion 2 C Number of

\mathrm{Cu}^{2+}

liberated

=\frac{1.6 \times 60}{2 \times 1.6 \times 10^{-19}}

=3 \times 10^{20}

Practice Current Electricity on Quantrex Academy →

More from Current Electricity