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JIPMER2017PhysicsDual Nature of Matter

The wavelength of a photon and the de-Broglie wavelength of an electron have the same value. Find the ratio of energy of photon to the kinetic energy of electron in terms of mass m , speed of light c and planck constant.

Options

  1. Am c h
  2. Bh m c
  3. C2 h m c
  4. D2 m c h

Correct answer

D. 2 m c h

Step-by-step solution

The de-Broglie wavelength h= h m v v= h m ...(i)E_p= h c (since is same )...(ii) Kinetic energy of photon = E_p E_e = h c / 1 2 1 m u^2 = 2 h c m v^2 Substituting value of v from Eq. (i), we get E_p E_e = 2 h c _m ( h m )^2 = 2 m c h

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