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JIPMER 2005
Exam
JIPMER
Year
2005
Subject
Physics
Chapter
Dual Nature of Matter

JIPMER 2005 · Physics · Dual Nature of Matter

If work function of a metal is 4.2 eV , the cut off wavelength is

If work function of a metal is 4.2 eV , the cut off wavelength is

Options

  1. A8000A˚8000 Å
  2. B7000A˚7000 Å
  3. C1472A˚1472 Å
  4. D2950A˚2950 Å

Correct answer

D. 2950A˚2950 Å

Step-by-step solution

Suppose the cut off wavelength is represented by λ0\lambda_0 So, hcλ0=\frac{h c}{\lambda_0}= work function =W0=W_0hcλ0=4.2×1.6×10−19λ0=6.6×10−34×3×1084.2×1.6×10−19=2946×10−10 m≈2950A˚\begin{aligned} \frac{h c}{\lambda_0} & =4.2 \times 1.6 \times 10^{-19} \\ \lambda_0 & =\frac{6.6 \times 10^{-34} \times 3 \times 10^8}{4.2 \times 1.6 \times 10^{-19}} \\ & =2946 \times 10^{-10} \mathrm{~m} \\ & \approx 2950 Å\end{aligned}$$
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