JIPMER2005PhysicsDual Nature of Matter
If work function of a metal is 4.2 eV , the cut off wavelength is
Options
- A8000 Å
- B7000 Å
- C1472 Å
- D2950 Å
Correct answer
D. 2950 Å
Step-by-step solution
Suppose the cut off wavelength is represented by ₀ So, h c ₀ = work function =W₀ aligned h c ₀ & =4.2 1.6 10⁻¹⁹ ₀ & = 6.6 10⁻³⁴ 3 10^8 4.2 1.6 10⁻¹⁹ & =2946 10⁻¹⁰ ~m & 2950 Å aligned