A charged particle is accelerated by a potential of 200 V . If its velocity is 8.4 × 10^8 ~m / s , then value of e / m for that particle is

Correct answer: C. 1.76 × 10^ 15 If electron is accelerated by voltage V , then its kinetic energy =(1)/(2) m v^2=q V aligned (q)/(m) & =(v^2)/(2 V) & =((8.4 × 10^8)^2)/(2 × 200)=1.76 × 10^ 15 aligned

JIPMER 2014

Exam: JIPMER
Year: 2014
Subject: Physics
Chapter: Electrostatics

JIPMER 2014 · Physics · Electrostatics

A charged particle is accelerated by a potential of 200 V . If its...

A charged particle is accelerated by a potential of 200 V . If its velocity is

8.4 \times 10^8 \mathrm{~m} / \mathrm{s}

, then value of

e / m

for that particle is

Options

A $17.6 \times 10^{16}$
B $14.5 \times 10^{12}$
C $1.76 \times 10^{15}$
D $1.45 \times 10^{15}$

Correct answer

C. $1.76 \times 10^{15}$

Step-by-step solution

If electron is accelerated by voltage

V

, then its kinetic energy

=\frac{1}{2} m v^2=q V

\begin{aligned} \frac{q}{m} & =\frac{v^2}{2 V} \\ & =\frac{\left(8.4 \times 10^8\right)^2}{2 \times 200}=1.76 \times 10^{15}\end{aligned}

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