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JIPMER 2016
Exam
JIPMER
Year
2016
Subject
Physics
Chapter
Electrostatics

JIPMER 2016 · Physics · Electrostatics

The concentric, conducting spherical shells X, Y and Z with radii...

The concentric, conducting spherical shells X,YX, Y and ZZ with radii r,2rr, 2 r and 3r3 r, respectively. XX and ZZ are connected by a conducting wire and YY is uniformly charged to charge QQ as shown in figure. Charges on shells XX and ZZ will be The concentric, conducting spherical shells X, Y and Z with radii r, 2 r and 3 r , respectively. X and Z are connected

Options

  1. Aqx=Q4,qz=−Q6q_x=\frac{Q}{4}, q_z=\frac{-Q}{6}
  2. Bqx=−Q4,qz=Q4q_x=\frac{-Q}{4}, q_z=\frac{Q}{4}
  3. Cqx=Q4,qz=−Q4q_x=\frac{Q}{4}, q_z=\frac{-Q}{4}
  4. Dqx=−Q6,qz=Q4q_x=\frac{-Q}{6}, q_z=\frac{Q}{4}

Correct answer

B. qx=−Q4,qz=Q4q_x=\frac{-Q}{4}, q_z=\frac{Q}{4}

Step-by-step solution

Let charges on XandZX and Z be qxandqZq_x and q_Z By conservation of charge, qx+qz=0⇒qz=−qxq_x+q_z=0 \Rightarrow q_z=-q_x The concentric, conducting spherical shells X, Y and Z with radii r, 2 r and 3 r , respectively. X and Z are connected ∴Vx=14πε0[qxr+Q2r+qz3r]Vz=14πε0[qx3r+Q3r+qz3r]\begin{aligned} \therefore \quad V_x & =\frac{1}{4 \pi \varepsilon_0}\left[\frac{q_x}{r}+\frac{Q}{2 r}+\frac{q_z}{3 r}\right] \\ V_z & =\frac{1}{4 \pi \varepsilon_0}\left[\frac{q_x}{3 r}+\frac{Q}{3 r}+\frac{q_z}{3 r}\right]\end{aligned} Since, XandZX and Z are connected. ∴Vx=VZ\therefore \quad V_x=V_Z⇒qXr+Q2r+qZ3r=qX3r+Q3r+qZ3r⇒2qX3=−Q6∴qX=−Q4∵qX+qZ=0⇒qZ=−qX=Q4\begin{aligned} \Rightarrow & & \frac{q_X}{r}+\frac{Q}{2 r}+\frac{q_Z}{3 r} & =\frac{q_X}{3 r}+\frac{Q}{3 r}+\frac{q_Z}{3 r} \\ \Rightarrow & & \frac{2 q_X}{3} & =\frac{-Q}{6} \\ & \therefore & q_X & =\frac{-Q}{4} \\ \because & & q_X+q_Z & =0 \Rightarrow q_Z=-q_X \\ & & & =\frac{Q}{4}\end{aligned}$$
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