JIPMER2004PhysicsElectrostatics
A charged particle is suspended in equilibrium in a uniform vertical electric field of intensity 20000 ~V / m . If mass of the particle is 9.6 10⁻¹⁶ ~kg , the charge on it and excess number of electrons on the-particle respectively are ( g =10 ~m / s ^2 )
Options
- A4.8 10⁻¹⁹ C , 3
- B5.8 10⁻¹⁹ C , 4
- C3.8 10⁻¹⁹ C , 2
- D28 10⁻¹⁹ C , 1
Correct answer
A. 4.8 10⁻¹⁹ C , 3
Step-by-step solution
Charge on the particle is given by aligned q E & =m g or q= m g E & = 9.6 10⁻¹⁶ 10 20000 =4.8 10⁻¹⁹ aligned When there is an excess of n electrons on the particle, then q=n e So, n= q e = 4.8 10⁻¹⁹ 1.6 10⁻¹⁹ =3