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JIPMER2004PhysicsKinetic Theory of Gases

The kinetic energy of one molecule of a gas at normal temperature and pressure will be (k=8.31 ~J / mole K )

Options

  1. A17 10^3 ~J
  2. B10.2 10^3 ~J
  3. C3.4 10^3 ~J
  4. D6.8 10^3 ~J

Correct answer

C. 3.4 10^3 ~J

Step-by-step solution

According to kinetic theory, K.E. of 1g-mole of an ideal gas, E= 3 2 R T Hence, K.E. at normal temperature 0^ C aligned & =273 ~K or E & = 3 2 8.31 273=3.4 10^3 ~J aligned

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