Two masses 10 kg and 20 kg respectively are connected by a massless spring as shown in figure. A force of 200 N acts on the 20 kg mass. At the instant shown is figure the 10 kg mass has acceleration of $12 \mathrm{~m} / \mathrm{s}^2$ . The value of acceleration of 20 kg mass is

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Two masses 10 kg and 20 kg respectively are connected by a massless spring as shown in figure. A force of 200 N acts on the 20 kg mass. At the instant shown is figure the 10 kg mass has acceleration of

12 \mathrm{~m} / \mathrm{s}^2

. The value of acceleration of 20 kg mass is Two masses 10 kg and 20 kg respectively are connected by a massless spring as shown in figure. A force of 200 N acts on

Two masses 10 kg and 20 kg respectively are connected by a massless spring as shown in figure. A force of 200 N acts on

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Correct answer: A. 4 ~m / s^2

Equation of motion of m_1=10 ~kg mass is F_1=m_1 a_1=10 × 12=120 ~N Force on 10 kg -mass is 120 N to the right. As action and reaction are equal and opposite, the reactions force F -on 20 kg mass F=120 ~N to the left. Equation of motion of mass m_2=20 ~kg is aligned 200-F & =20 a_2 200-120 & =20 a_2 20 a_2 & =80 a_2=(80)/(20) & =4 ~m / s^2 aligned

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