JIPMER2017PhysicsLaws of Motion
A long block A of mass M is at rest on a smooth horizontal surface. A small block B of mass M / 2 is placed on A at one end and projected along A with some velocity v . The coefficient of friction between the block is . Then, the accelerations of blocks A and B before reaching a common velocity will be respectively
Options
- Ag 2 (towards right), g 2 (towards left)
- Bg (towards right), g (towards left)
- Cg 2 (towards right), g (towards left)
- Dg (towards right), g 2 (towards left)
Correct answer
C. g 2 (towards right), g (towards left)
Step-by-step solution
The force causing the motion of A is frictional force between A and B , So, acceleration of A M_B g=M_A a_A a_A= ( M_B M_A ) g= g 2 (towards right) Block B experiences frictions force toward left M_B a_B= M_B g a_B= g towards left