A light string passes over a frictionless pulley. To one of its ends a mass of 8 kg is attached. To its other end two masses of 7 kg each are attached. The acceleration of the system will be

Step-by-step solution

From free body diagram of body A , m₁ a=T₁-m₁ g ....(i) For body B , m₂ a =m₂ g+T₂-T₁ ...(ii) For body C, m₃ a=m₃ g-T₂ ....(iii) On solving Eqs. (i), (ii) and (iii), we get a= [ (m₂+m₃ )-m₁ ] g m₁+m₂+m₃ As, aligned m₁ & =8 ~kg , m₂=m₃=7 ~kg a & = 6 22 ~g =0.27 ~g aligned