The lower end of capillary tube is immresed in mercury. The level of mercury in the tube is found to be 2 cm below the outer level. If the same tube is immersed in water, upto what height will the water rise in the capillary?

Step-by-step solution

Given data: Level of mercury in the tube is, ( h ^ =2 ~cm ). Level of mercury in the tube is given as: ( h ^ = 2 ~T ^ ^ r ^ g . (1) ) where ( ^ ) is the density of mercury. Level of water in the tube is given as: ( h = 2 ~T r g (2) ) where ( ) is the density of water. Here, the same capillary is immersed in both the liquids hence, the radius of the capillary is same i.e. (r ) Using the standard values for variables and taking ( ^ =135^ ), in equation (1) gives: ( aligned & 2= 2(484.5) 135^ r(13.6)(980) & r= 685.083