JIPMER2013PhysicsMechanical Properties of Fluids
The work done in increasing the size of a soap film for 10 ~cm 6 ~m to 10 ~cm 11 ~cm is 3 10⁻⁴ ~J . The surface tension of the film is
Options
- A1.0 10⁻² ~N / m
- B6.0 10⁻² ~N / m
- C3.0 10⁻² ~N / m
- D1.5 10⁻² ~N / m
Correct answer
C. 3.0 10⁻² ~N / m
Step-by-step solution
aligned & Work done = Area increased & So, surface tension & aligned S_T & = 3 10⁻⁴ 2 (10 11-10 6) 10⁻⁴ & =3 10⁻² ~N / m aligned aligned