The cylindrical tube of a spray pump has a cross-section of 8 ~cm^2...

According to equation of continuity, $a v=$ constant $\therefore$ For tube, \left(8 \times 10^{-4}\right) \times\left(\frac{0.15}{60}\right)=a_1 v_1$For holes,$\quad\left(40 \times 10^{-8}\right) \times v=a_2 v_2 \therefore \quad a_2 v_2=a_1 v_1 \therefore 40 \times 10^{-8} \times v=\frac{8 \times 10^{-4} \times 0.15}{60} \Rightarrow \quad v=\frac{8 \times 10^{-4} \times 0.15}{40 \times 10^{-8} \times 60} =5 \mathrm{~m} / \mathrm{s}