An ice-cube of density 900 ~kg / m^3 is floating in water of density 1000 ~kg / m^3 . The percentage of volume of ice-cube outside the water is

Correct answer: C. 10 \% The percentage of volume of ice cube outside the water is aligned & = _ water - _ ice _ water × 100 & =(1000-900)/(1000) × 100=10 \% aligned

JIPMER 2005

Exam: JIPMER
Year: 2005
Subject: Physics
Chapter: Mechanical Properties of Fluids

JIPMER 2005 · Physics · Mechanical Properties of Fluids

An ice-cube of density 900 ~kg / m^3 is floating in water of...

An ice-cube of density

900 \mathrm{~kg} / \mathrm{m}^3

is floating in water of density

1000 \mathrm{~kg} / \mathrm{m}^3

. The percentage of volume of ice-cube outside the water is

Options

A $20 \%$
B $35 \%$
C $10 \%$
D $25 \%$

Correct answer

C. $10 \%$

Step-by-step solution

The percentage of volume of ice cube outside the water is

\begin{aligned} & =\frac{\rho_{\text{water }}-\rho_{\text{ice }}}{\rho_{\text{water }}} \times 100 \\ & =\frac{1000-900}{1000} \times 100=10 \%\end{aligned}

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