JIPMER2012PhysicsRay Optics
A vessel of height 2 d is half filled with a liquid of refractive index 2 and the other half with a liquid of refractive index n (the given liquids are immiscible). Then, the apparent depth of the inner surface of the bottom of the vessel (neglecting the thickness of the bottom of the vessel) will be
Options
- An d(n+ 2 )
- Bd(n+ 2 ) n 2
- C2 n d(n+ 2 )
- Dn d d+ 2 n
Correct answer
B. d(n+ 2 ) n 2
Step-by-step solution
Refractive index = Real depth (d) Apparent depth (x) For 1st liquid, 2 = d x₁ x₁= d 2 Similarly, for 2nd liquid, n= d x₂ x₂= d n Total apparent depth =x₁+x₂= d 2 + d n = d(n+ 2 ) n 2