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JIPMER 2006
Exam
JIPMER
Year
2006
Subject
Physics
Chapter
Ray Optics

JIPMER 2006 · Physics · Ray Optics

The time taken by light to pass through 4 mm thick glass slab of...

The time taken by light to pass through 4 mm thick glass slab of refractive index 1.5 will be : (velocity of light in air =3×108 m/s=3 \times 10^8 \mathrm{~m} / \mathrm{s} )

Options

  1. A8×10−11 s8 \times 10^{-11} \mathrm{~s}
  2. B2×10−11 s2 \times 10^{-11} \mathrm{~s}
  3. C8×10−8 s8 \times 10^{-8} \mathrm{~s}
  4. D2×10−8 s2 \times 10^{-8} \mathrm{~s}

Correct answer

B. 2×10−11 s2 \times 10^{-11} \mathrm{~s}

Step-by-step solution

Time taken by light t=μdc=1.5×4×10−33×108=2×10−11 s\begin{aligned} t & =\frac{\mu d}{c} \\ & =\frac{1.5 \times 4 \times 10^{-3}}{3 \times 10^8}=2 \times 10^{-11} \mathrm{~s}\end{aligned}
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