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JIPMER 2014
Exam
JIPMER
Year
2014
Subject
Physics
Chapter
Thermal Properties of Matter

JIPMER 2014 · Physics · Thermal Properties of Matter

50 g ice at 0^ C in insulator vessel, 50 g water of 100^ C is mixed...

50 g ice at 0∘C0^{\circ} \mathrm{C} in insulator vessel, 50 g water of 100∘C100^{\circ} \mathrm{C} is mixed in it, then final temperature of the mixture is (neglect the heat loss)

Options

  1. A10∘C10^{\circ} \mathrm{C}
  2. B0∘<<Tm<20∘C0^{\circ}\lt \lt T_m \lt 20^{\circ} \mathrm{C}
  3. C20∘C20^{\circ} \mathrm{C}
  4. Dabove 20∘C20^{\circ} \mathrm{C}

Correct answer

A. 10∘C10^{\circ} \mathrm{C}

Step-by-step solution

According to calorimeter principle, Heat given = Heat taken m1s1(100−t)=mL+m2s2(t−0)m_1 s_1(100-t)=m L+m_2 s_2(t-0)50×1(100−t)=50×80+50×1(t−0)t=10∘C\begin{aligned} 50 \times 1(100-t) & =50 \times 80+50 \times 1(t-0) \\ t & =10^{\circ} \mathrm{C}\end{aligned}$$
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