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JIPMER 2011
Exam
JIPMER
Year
2011
Subject
Physics
Chapter
Thermal Properties of Matter

JIPMER 2011 · Physics · Thermal Properties of Matter

The temperature of the sun can be found out by using

The temperature of the sun can be found out by using

Options

  1. AWien's displacement law
  2. BKepler's law of motion
  3. CStefan's Boltzmann law
  4. DPlanck's law

Correct answer

C. Stefan's Boltzmann law

Step-by-step solution

We know solar constant (heat flux falling on the earth), S=1350 W/m2\mathrm{S}=1350 \mathrm{~W} / \mathrm{m}^2 Let EE be the energy emitted by the sun per second per unit area. Then, the total energy emitted by the sun is one second 4πR2E4 \pi R^2 E. This energy is falling on a sphere of radius equal to the radius of the Earth's orbit around the sun i.e., on a sphere of surface area 4πr24 \pi \mathrm{r}^2. Energy falling per unit area =4πR2E4πr2=ER2r2=S=\frac{4 \pi R^2 E}{4 \pi r^2}=\frac{E R^2}{r^2}=S Using Stefan Boltzman's law: E=σT4\mathrm{E}=\sigma \mathrm{T}^4 T=(S×R2σ×r2)14=5760 K\mathrm{T}=\left(\frac{\mathrm{S} \times \mathrm{R}^2}{\sigma \times \mathrm{r}^2}\right)^{\frac{1}{4}}=5760 \mathrm{~K}
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