JIPMER2005PhysicsThermal Properties of Matter
A body of specific heat 0.2 kcal / kg ^ C is heated through 100^ C . The percentage increase in its mass is
Options
- A9 %
- B9.3 10⁻¹¹ %
- C10 %
- DNone of these
Correct answer
B. 9.3 10⁻¹¹ %
Step-by-step solution
Heat taken by the given body =m c specific heat of body =0.2 kcal / kg ^ C , final temperature of the body .=100^ C aligned E & =m 0.2 100=20 mkcal & =20 ~m 4.2 10^3 ~J aligned Now gain in mass is given by m= E C^2 ( E=m c^2 )= 20 ~m 4.2 10^3 (3 10^8 )^2 Therefore, percentage increase in mass is given by aligned & = m m 100 & = 20 m 4.2 10^3 (3 10^8 )^2 m 100 & =9.3 10⁻¹¹ % aligned