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JIPMER 2007
Exam
JIPMER
Year
2007
Subject
Physics
Chapter
Thermal Properties of Matter

JIPMER 2007 · Physics · Thermal Properties of Matter

The temperature of inversion of a thermocouple is 620^ C and the...

The temperature of inversion of a thermocouple is 620∘C620^{\circ} \mathrm{C} and the neutral temperature is 300∘C300^{\circ} \mathrm{C}, what is the temperature of cold junction?

Options

  1. A20∘C20^{\circ} \mathrm{C}
  2. B320∘C320^{\circ} \mathrm{C}
  3. C−20∘C-20^{\circ} \mathrm{C}
  4. D40∘C40^{\circ} \mathrm{C}

Correct answer

C. −20∘C-20^{\circ} \mathrm{C}

Step-by-step solution

The temperature of inversion is higher than the neutral temperature by the same amount as the neutral temperature is higher than the temperature of cold junction. As per Key Idea tn−t0=ti−tn⇒t0=2tn−tit_n-t_0=t_i-t_n \Rightarrow t_0=2 t_n-t_i Given, ti=620∘C,tn=300∘Ct_i=620^{\circ} \mathrm{C}, t_n=300^{\circ} \mathrm{C} Hence, t0=t_0= temperature of cold junction =2×300−620=600−620=−20∘C\begin{aligned} & =2 \times 300-620 \\ & =600-620=-20^{\circ} \mathrm{C}\end{aligned} NOTE: Neutral temperature does not change for a metal whether the temperature of cold junction and inversion temperature change by any value.
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