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JIPMER 2018
Exam
JIPMER
Year
2018
Subject
Physics
Chapter
Thermodynamics

JIPMER 2018 · Physics · Thermodynamics

If a machine perform 4000 J output work and 1000 J is inside loss...

If a machine perform 4000 J output work and 1000 J is inside loss due to friction, then the find efficiency?

Options

  1. A80%80 \%
  2. B30%30 \%
  3. C25%25 \%
  4. D60%60 \%

Correct answer

A. 80%80 \%

Step-by-step solution

∵\because Efficiency = output work  input work ×100=WoWi×100=\frac{\text{ output work }}{\text{ input work }} \times 100=\frac{\mathrm{W}_{\mathrm{o}}}{\mathrm{W}_{\mathrm{i}}} \times 100∵Wo=4000J∴Wi=4000+1000=5000J∴ Efficiency =40005000×100=80%\begin{aligned} & \because \mathrm{W}_{\mathrm{o}}=4000 \mathrm{ J} \\ & \therefore \mathrm{W}_{\mathrm{i}}=4000+1000=5000 \mathrm{ J} \\ & \therefore \text{ Efficiency }=\frac{4000}{5000} \times 100=80 \%\end{aligned}$$
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