The work of 146 kJ is performed in order to compress one kilo mole of a gas adiabatically and in this process the temperature of the gas increases by 7^ C . The gas is (R=8.3 ~J ~mol ⁻¹ ~K ⁻¹ )

Step-by-step solution

For adiabatic process, array cc & d Q=0 So, & d U=- W & n C_V d T=+146 10^3 ~J & n f R 2 7=146 10^3 & [f Degree of freedom ] & 10^3 f 8.3 7 2 =146 10^3 & f=5.02 5 array So, it is a diatomic gas.