JIPMER 2009
- Exam
- JIPMER
- Year
- 2009
- Subject
- Physics
- Chapter
- Thermodynamics
JIPMER 2009 · Physics · Thermodynamics
The work of 146 kJ is performed in order to compress one kilo mole...
The work of 146 kJ is performed in order to compress one kilo mole of a gas adiabatically and in this process the temperature of the gas increases by . The gas is
Options
- Adiatomic
- Btriatomic
- Ca mixture of monoatomic and diatomic
- Dmonoatomic
Correct answer
A. diatomic
Step-by-step solution
For adiabatic process,
$\begin{array}{cc}
& d Q=0 \\
\text{ So, } & d U=-\Delta W \\
\Rightarrow & n C_V d T=+146 \times 10^3 \mathrm{~J} \\
\Rightarrow & \frac{n f R}{2} \times 7=146 \times 10^3 \\
& {[f \rightarrow \text{ Degree\text{ of }\text{ freedom } }]} \\
\Rightarrow & \frac{10^3 \times f \times 8.3 \times 7}{2}=146 \times 10^3 \\
& f=5.02 \approx 5
\end{array}
So, it is a diatomic gas.$