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JIPMER 2005
Exam
JIPMER
Year
2005
Subject
Physics
Chapter
Units and Dimensions

JIPMER 2005 · Physics · Units and Dimensions

The dimensional formula for Young's modulus is

The dimensional formula for Young's modulus is

Options

  1. AML−1 T−2\mathrm{ML}^{-1} \mathrm{~T}^{-2}
  2. BM0LT−2\mathrm{M}^0 \mathrm{LT}^{-2}
  3. CMLT−2\mathrm{MLT}^{-2}
  4. DML2 T−2\mathrm{ML}^2 \mathrm{~T}^{-2}

Correct answer

A. ML−1 T−2\mathrm{ML}^{-1} \mathrm{~T}^{-2}

Step-by-step solution

The formula for the Young's modulus Y= stress  strain \mathrm{Y}=\frac{\text{ stress }}{\text{ strain }} Dimensions of Y=ML−1T−2M0L0T0=ML−1T−2\begin{aligned} \mathrm{Y} & =\frac{\mathrm{ML}^{-1} \mathrm{ T}^{-2}}{\mathrm{M}^0 \mathrm{ L}^0 \mathrm{ T}^0} \\ & =\mathrm{ML}^{-1} \mathrm{ T}^{-2}\end{aligned}
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